Consider the following compounds:I. CH_3-CH_2 | vedclass

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(B) The basic strength of amines depends on the availability of the lone pair on the nitrogen atom.$1$. In $CH_3-CH_2-NH_2$ (Ethylamine),the ethyl gro

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$I > II > III$

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(B) The basic strength of amines depends on the availability of the lone pair on the nitrogen atom.$1$. In $CH_3-CH_2-NH_2$ (Ethylamine),the ethyl group is an electron-donating group ($+I$ effect),which increases the electron density on the nitrogen atom,making it the most basic.$2$. In $Ph-CH_2-NH_2$ (Benzylamine),the phenyl group is attached to the $CH_2$ group,which is separated from the nitrogen by a $CH_2$ spacer. The phenyl group exerts an electron-withdrawing effect ($-I$ effect),making it less basic than ethylamine.$3$. In $Ph-NH_2$ (Aniline),the lone pair on the nitrogen atom is in conjugation with the benzene ring (delocalized),making it the least basic.Therefore,the correct order of basic strength is $I > II > III$.

Consider the following compounds:
$I. CH_3-CH_2-NH_2$
$II. Ph-CH_2-NH_2$
$III. Ph-NH_2$
The correct order of their basic strength is:

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Consider the following compounds:$I. CH_3-CH_2-NH_2$$II. Ph-CH_2-NH_2$$III. Ph-NH_2$The correct order of their basic strength is: