Consider the following frequency distribution | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the median class,we first convert the discontinuous class intervals into continuous ones by adjusting the boundaries. The difference betwe

Vedclass · Accepted Answer

$17.5$

Vedclass · Answer

(A) To find the median class,we first convert the discontinuous class intervals into continuous ones by adjusting the boundaries. The difference between the upper limit of one class and the lower limit of the next is $1$. Thus,we subtract $0.5$ from the lower limit and add $0.5$ to the upper limit.						Class			Frequency $(f)$			Cumulative Frequency $(cf)$							$-0.5-5.5$			$13$			$13$							$5.5-11.5$			$10$			$23$							$11.5-17.5$			$15$			$38$							$17.5-23.5$			$8$			$46$							$23.5-29.5$			$11$			$57$			The total frequency $N = 57$. The median position is $N/2 = 57/2 = 28.5$. The cumulative frequency just greater than $28.5$ is $38$,which corresponds to the class interval $11.5-17.5$. Therefore,the median class is $11.5-17.5$. The upper limit of this class is $17.5$.

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$43$	$55$	$37$	$18$

Height (in $cm$)	Frequency	Cumulative frequency
$150-155$	$12$	$a$
$155-160$	$b$	$25$
$160-165$	$10$	$c$
$165-170$	$d$	$43$
$170-175$	$e$	$48$
$175-180$	$2$	$f$
Total	$50$	-

Consider the following frequency distribution:

Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$

Frequency $13$ $10$ $15$ $8$ $11$

The upper limit of the median class is

Similar Questions

If $Z+M=34$ and $M+\bar{x}=40,$ then $M=\ldots \ldots \ldots . . .$

Midpoint (Midvalue) of the class $15-30$ is ........

To draw the 'less than' type Ogive,........... is represented on the $X$-axis.

Find the mode of the following frequency distribution:

Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$

Frequency $8$ $12$ $27$ $43$ $55$ $37$ $18$

Find the unknown entries $a, b, c, d, e, f$ in the following distribution of heights of students in a class:

Height (in $cm$) Frequency Cumulative frequency

$150-155$ $12$ $a$

$155-160$ $b$ $25$

$160-165$ $10$ $c$

$165-170$ $d$ $43$

$170-175$ $e$ $48$

$175-180$ $2$ $f$

Total $50$ -

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Class	$0-5$	$6-11$	$12-17$	$18-23$	$24-29$
Frequency	$13$	$10$	$15$	$8$	$11$

Consider the following frequency distribution: Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$ Frequency $13$ $10$ $15$ $8$ $11$ The upper limit of the median class is