Consider the following pairs:

Order	Property
$(A)$ $NO_2 > O_3 > H_2O$	Bond angle
$(B)$ $H_2O > HF > NH_3$	Dipole moment
$(C)$ $I_2 > F_2 > N_2$	Bond length

Which of the above pairs are correctly matched?

The formation of $PH_4^+$ is difficult compared to $NH_4^+$ because

Identify the set of molecules/ions that are isoelectronic.

Observe the following structure. The formal charges on the atoms $1, 2, 3$ respectively are:

The number of $3c-2e$ bond and $2c-2e$ bond present in $Be_2(CH_3)_4$ are $ . . . . . . $ and $ . . . . . . $ respectively.

Given below are statements about some molecules/ions. Identify the $CORRECT$ statements.
$A$. The dipole moment value of $NF_3$ is higher than that of $NH_3$.
$B$. The dipole moment value of $BeH_2$ is zero.
$C$. The bond order of $O_2^{2-}$ and $F_2$ is same.
$D$. The formal charge on the central oxygen atom of ozone is $-1$.
$E$. In $NO_2$, all the three atoms satisfy the octet rule, hence it is very stable.
Choose the correct answer from the options given below: