Consider the following reaction:
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(D) The reaction involves the cleavage of an ether, benzyl phenyl ether $(C_6H_5-O-CH_2-C_6H_5)$, with hydrogen iodide $(HI)$.
In the reaction of an

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Statement $I$ is false but Statement $II$ is true

Vedclass · Answer

(D) The reaction involves the cleavage of an ether, benzyl phenyl ether $(C_6H_5-O-CH_2-C_6H_5)$, with hydrogen iodide $(HI)$.
In the reaction of an alkyl aryl ether with $HI$, the cleavage occurs such that the alkyl group forms an alkyl iodide and the aryl group forms a phenol.
This is because the $O-C_{aryl}$ bond has partial double bond character due to resonance and is stronger, while the $O-C_{alkyl}$ bond is weaker and undergoes nucleophilic substitution.
Here, the $O-CH_2C_6H_5$ bond breaks to form benzyl iodide $(C_6H_5CH_2I)$ and phenol $(C_6H_5OH)$.
Therefore, Statement $I$ is false because the products are benzyl iodide and phenol, not benzyl alcohol and iodobenzene.
Statement $II$ is true because the $O-CH_2$ bond is indeed the one that undergoes cleavage.

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