Consider the following sequence of reactions. | vedclass

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(C) $1$. The starting material is $4-$nitrotoluene $(C_7H_7NO_2)$, which has a molar mass of $(7 	imes 12) + (7 	imes 1) + 14 + (2 	imes 16) = 84 +

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$228$

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(C) $1$. The starting material is $4-$nitrotoluene $(C_7H_7NO_2)$, which has a molar mass of $(7 	imes 12) + (7 	imes 1) + 14 + (2 	imes 16) = 84 + 7 + 14 + 32 = 137 \ g \ mol^{-1}$.$2$. Reduction of $4-$nitrotoluene with $Sn/HCl$ gives $p-$toluidine ($A$, $C_7H_9N$).$3$. Acetylation of $p-$toluidine with $(CH_3CO)_2O$ gives $N-(p-tolyl)acetamide$ $(C_9H_{11}NO)$.$4$. Bromination of $N-(p-tolyl)acetamide$ with $Br_2/AcOH$ gives $2-bromo-4-methylacetanilide$ ($B$, $C_9H_{10}BrNO$).$5$. The molar mass of $B$ $(C_9H_{10}BrNO)$ is $(9 	imes 12) + (10 	imes 1) + 14 + 80 + 16 = 108 + 10 + 14 + 80 + 16 = 228 \ g \ mol^{-1}$.$6$. Moles of $4-$nitrotoluene $= \frac{137 	imes 10^{-3} \ g}{137 \ g \ mol^{-1}} = 0.001 \ mol$.$7$. Since the stoichiometry is $1:1$, moles of $B = 0.001 \ mol$.$8$. Mass of $B = 0.001 \ mol 	imes 228 \ g \ mol^{-1} = 0.228 \ g = 228 \ mg$.

Consider the following sequence of reactions. Assuming that the reaction proceeds to completion, then $137 \ mg$ of $4-$nitrotoluene will produce . . . . . . $mg$ of $B$. (Given molar mass in $g \ mol^{-1}: H = 1, C = 12, N = 14, O = 16, Br = 80$)

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