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(A) The given reaction is a coupling reaction of benzene diazonium chloride with a phenol or amine in a basic medium to form an azo dye.The reaction o

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(A) The given reaction is a coupling reaction of benzene diazonium chloride with a phenol or amine in a basic medium to form an azo dye.The reaction of benzene diazonium chloride with $\beta$-naphthol in the presence of $NaOH$ (basic medium) yields an orange-red azo dye.The chemical equation is:$C_6H_5N_2^+Cl^- + \beta	ext{-Naphthol} \xrightarrow{NaOH} 	ext{Orange-red dye}$

Which among the following represents reagent $A$ in the given reaction?
$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

Similar Questions

What are $X$ and $Y$ respectively in the following set of reactions?

Among the compounds given below,the order of basicity is:
$(I)$ Piperidine
$(II)$ Pyridine
$(III)$ Morpholine
$(IV)$ Pyrrole

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.

The product $(A)$ of the given reaction is:

The product $(A)$ of the given reaction is:

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Which among the following represents reagent $A$ in the given reaction?$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

Similar Questions

What are $X$ and $Y$ respectively in the following set of reactions?

Among the compounds given below,the order of basicity is:$(I)$ Piperidine$(II)$ Pyridine$(III)$ Morpholine$(IV)$ Pyrrole

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$Butter yellow is the product of the above reaction.

The product $(A)$ of the given reaction is:

The product $(A)$ of the given reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which among the following represents reagent $A$ in the given reaction?
$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

Among the compounds given below,the order of basicity is:
$(I)$ Piperidine
$(II)$ Pyridine
$(III)$ Morpholine
$(IV)$ Pyrrole

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.