The product $(A)$ of the given reaction is:

  • A
    $1,2,3,4-$tetrahydroquinoline
  • B
    $1,2,3,4-$tetrahydroisoquinoline
  • C
    Indoline
  • D
    $4-$chlorobutylbenzene

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Similar Questions

Consider the above sequence of reactions. The number of bromine atom$(s)$ in the final product $(P)$ will be:

An organic compound $A$ on reduction gives compound $B$,which on reaction with trichloromethane and caustic potash forms $C$. The compound $C$ on catalytic reduction gives $N$-methylbenzenamine. The compound $A$ is,

Give a plausible explanation for each of the following:
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?

In the given reaction,$A$ is:
$A$ $\xrightarrow{\text{Reduction}} B$ $\xrightarrow{HNO_2} C_2H_5OH$

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Match the compounds given in List-$I$ with the items given in List-$II$.
List-$I$ List-$II$
$I.$ Benzenesulphonyl Chloride $A.$ Zwitterion
$II.$ Sulphanilic acid $B.$ Hinsberg reagent
$III.$ Alkyl Diazonium salts $C.$ Dyes
$IV.$ Aryl Diazonium salts $D.$ Conversion to alcohols

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