Ph-NH_2 xrightarrow{CH_3Cl (2 mole)} (A) xr | vedclass

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(D) $1$. The reaction of aniline $(Ph-NH_2)$ with $2 \ mole$ of $CH_3Cl$ leads to the formation of $N,N$-dimethylaniline as product $(A)$.$Ph-NH_2 + 2

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(D) $1$. The reaction of aniline $(Ph-NH_2)$ with $2 \ mole$ of $CH_3Cl$ leads to the formation of $N,N$-dimethylaniline as product $(A)$.$Ph-NH_2 + 2CH_3Cl \rightarrow Ph-N(CH_3)_2 + 2HCl$$2$. $N,N$-dimethylaniline $(A)$ then undergoes an electrophilic aromatic substitution reaction with benzenediazonium chloride $(Ph-N_2^+ Cl^-)$.$3$. The $-N(CH_3)_2$ group is a strong activating group and is ortho/para directing. Due to steric hindrance,the para-substitution is the major product.$4$. The resulting product $(B)$ is $p$-dimethylaminoazobenzene,which is commonly known as Butter Yellow.Structure of $(B)$: $Ph-N=N-C_6H_4-N(CH_3)_2$ (para-substituted).

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.

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$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$Butter yellow is the product of the above reaction.