Consider the following sequence of reactions: | vedclass

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(B) Formaldehyde $(HCHO)$ reacts with $HCN$ (generated from $NaCN$ and $dil. H_2SO_4$) to form formaldehyde cyanohydrin $(HO-CH_2-CN)$ as product $A$.

Vedclass · Accepted Answer

$HO-CH_2-CH_2-NH_2$

Vedclass · Answer

(B) Formaldehyde $(HCHO)$ reacts with $HCN$ (generated from $NaCN$ and $dil. H_2SO_4$) to form formaldehyde cyanohydrin $(HO-CH_2-CN)$ as product $A$.The reduction of the nitrile group $(-CN)$ in product $A$ using $H_2/Pt$ yields the primary amine $HO-CH_2-CH_2-NH_2$ ($2$-aminoethanol) as product $B$.Reaction:$HCHO + HCN$ $\rightarrow HO-CH_2-CN$ $\xrightarrow[Pt]{2H_2} HO-CH_2-CH_2-NH_2$

Consider the following sequence of reactions: $HCHO$ $\xrightarrow[dil. H_2SO_4]{NaCN} A$ $\xrightarrow[Pt]{H_2} B$. The product $(B)$ is:

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