Consider the following statements:r: text{If | vedclass

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(A) $1$. For $r$: $p 	o q$ is false only when $p=T$ and $q=F$. In this case, $p \vee q = T \vee F = T$. Since the statement says $p \vee q$ is false,

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$T, T$

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(A) $1$. For $r$: $p 	o q$ is false only when $p=T$ and $q=F$. In this case, $p \vee q = T \vee F = T$. Since the statement says $p \vee q$ is false, $r$ is false $(F)$.$2$. For $s$: $p \leftrightarrow q$ is false when $p$ and $q$ have different truth values ($T, F$ or $F, T$).- If $p=T, q=F$, then $p \vee q = T$. Statement $s$ claims it is false, so $s$ is false $(F)$.- If $p=F, q=T$, then $p \vee q = T$. Statement $s$ claims it is false, so $s$ is false $(F)$.Since $s$ is false in all cases where the condition is met, $s$ is false $(F)$.$3$. Now, $r=F$ and $s=F$. The truth value of $r 	o s$ is $F 	o F = T$. The truth value of $s 	o r$ is $F 	o F = T$.

Consider the following statements:
$r: \text{If } p \to q \text{ is false, then } p \vee q \text{ is false.}$
$s: \text{If } p \leftrightarrow q \text{ is false, then } p \vee q \text{ is false.}$
The truth values of $r \to s$ and $s \to r$ are respectively:

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Consider the following statements:$r: \text{If } p \to q \text{ is false, then } p \vee q \text{ is false.}$$s: \text{If } p \leftrightarrow q \text{ is false, then } p \vee q \text{ is false.}$The truth values of $r \to s$ and $s \to r$ are respectively: