Consider the following two half-cell reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The overall cell reaction is obtained by subtracting the first half-reaction from the second (multiplied by $3$): $3 	imes (\frac{1}{2}O_2 + 2H^+

Vedclass · Accepted Answer

$561$

Vedclass · Answer

(A) The overall cell reaction is obtained by subtracting the first half-reaction from the second (multiplied by $3$): $3 	imes (\frac{1}{2}O_2 + 2H^+ + 2e^- ightarrow H_2O) \implies 1.5O_2 + 6H^+ + 6e^- ightarrow 3H_2O$ $(E^{\ominus} = 1.23 	ext{ V})$$CH_3OH + H_2O ightarrow CO_2 + 6H^+ + 6e^-$ $(E^{\ominus} = -0.02 	ext{ V})$Adding these, we get: $CH_3OH + 1.5O_2 ightarrow CO_2 + 2H_2O$.$E^{\ominus}_{cell} = 1.23 	ext{ V} - 0.02 	ext{ V} = 1.21 	ext{ V}$.The number of electrons transferred, $n = 6$.The standard Gibbs free energy change is $\Delta G^{\ominus} = -nFE^{\ominus} = -6 	imes 96500 	ext{ C mol}^{-1} 	imes 1.21 	ext{ V} = -700770 	ext{ J mol}^{-1}$.The work derived from the cell at $80\%$ efficiency is $W = 0.8 	imes |\Delta G^{\ominus}| = 0.8 	imes 700770 	ext{ J} = 560616 	ext{ J}$.Work done in isothermal compression against constant pressure is $W = P \Delta V$.Given $P = 1 	ext{ kPa} = 1000 	ext{ Pa}$, we have $560616 = 1000 	imes \Delta V$.$\Delta V = 560.616 	ext{ m}^3$.Rounding to the nearest integer, $\Delta V = 561 	ext{ m}^3$.

$A$. Leclanche cell	$1$. Converts energy of combustion into electrical energy
$B$. Fuel cell	$2$. Rechargeable cell
$C$. Ni-Cd cell	$3$. At anode,$Zn \longrightarrow Zn^{2+} + 2e^{-}$

Similar Questions

Which of the following is not correct?

The values of the limiting molar conductivity $(\lambda^0)$ for $NaCl$,$HCl$ and $NaOAc$ are $126.4$,$425.9$ and $91.0 \, S \, cm^2 \, mol^{-1}$,respectively. For $HOAc$,$\Lambda^0$ in $S \, cm^2 \, mol^{-1}$ is

Match the entries from Column $I$ and Column $II$ and choose the correct order.
$A$. Leclanche cell $1$. Converts energy of combustion into electrical energy
$B$. Fuel cell $2$. Rechargeable cell
$C$. Ni-Cd cell $3$. At anode,$Zn \longrightarrow Zn^{2+} + 2e^{-}$

At $25^\circ \text{C}$,given the following data: $Ag_{(s)} + I^-_{(aq)} \rightarrow AgI_{(s)} + e^-$,$E^o = 0.152 \ V$; $Ag_{(s)} \rightarrow Ag^+_{(aq)} + e^-$,$E^o = -0.800 \ V$. What is the value of $\log \ K_{sp}$ for $AgI$? (where $K_{sp} = \text{solubility product}$)

$Cu^{+}$ ion is not stable in aqueous solution because of disproportionation reaction. $E^o$ value for disproportionation of $Cu^{+}$ is .............. $V$ (Given $E^o_{Cu^{2+}/Cu^{+}} = 0.15 \ V$,$E^o_{Cu^{2+}/Cu} = 0.34 \ V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module