Consider the given reaction: CH_3-CH=CH-CH_2- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction proceeds via an $S_N1$ mechanism.First,the hydroxyl group is protonated by $HBr$ and leaves as water to form a resonance-stabilized a

Vedclass · Accepted Answer

$CH_3-CH(Br)-CH=CH_2$

Vedclass · Answer

(B) The reaction proceeds via an $S_N1$ mechanism.First,the hydroxyl group is protonated by $HBr$ and leaves as water to form a resonance-stabilized allylic carbocation: $[CH_3-CH=CH-CH_2^+ \leftrightarrow CH_3-CH^+-CH=CH_2]$.The nucleophile $Br^-$ then attacks the more stable secondary carbocation site,leading to the formation of $CH_3-CH(Br)-CH=CH_2$ as the major product $[P]$.

Consider the given reaction: $CH_3-CH=CH-CH_2-OH \xrightarrow[S_N1]{HBr} [P]$. In the given reaction,the product $[P]$ is:

Similar Questions

The product of which of the following reactions undergoes hydrolysis by the $S_N 1$ mechanism?

What is the product of the hydrolysis of trichloromethane with $KOH$?

Alkyl halides react with $Mg$ in dry ether to form

Which of the following is likely to undergo racemization during alkaline hydrolysis?

$2$-chlorobutane $+ Cl_2 \rightarrow C_4H_8Cl_2$ (isomers)
Total number of optically active isomers shown by $C_4H_8Cl_2$,obtained in the above reaction is......................

Vedclass Test Series

Exam Paper Generator

Online Exam Module