Consider the reactions:(i) (CH_3)_2CHCH_2Br | vedclass

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(B) In reaction $(i)$,the solvent is $C_2H_5OH$,which is a weak nucleophile and a polar protic solvent. This promotes the formation of a carbocation i

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$S_N1$ and $S_N2$

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(B) In reaction $(i)$,the solvent is $C_2H_5OH$,which is a weak nucleophile and a polar protic solvent. This promotes the formation of a carbocation intermediate,characteristic of an $S_N1$ mechanism.In reaction $(ii)$,the reagent is $C_2H_5O^-$,which is a strong nucleophile. Strong nucleophiles favor the $S_N2$ mechanism,where the nucleophile attacks the substrate directly in a single step.Therefore,the mechanisms are $S_N1$ and $S_N2$ respectively.

Consider the reactions:
$(i) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5OH} (CH_3)_2CHCH_2OC_2H_5 + HBr$
$(ii) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5O^-} (CH_3)_2CHCH_2OC_2H_5 + Br^-$
The mechanisms of reaction $(i)$ and $(ii)$ are respectively:

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Consider the reactions:$(i) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5OH} (CH_3)_2CHCH_2OC_2H_5 + HBr$$(ii) \ (CH_3)_2CHCH_2Br \xrightarrow{C_2H_5O^-} (CH_3)_2CHCH_2OC_2H_5 + Br^-$The mechanisms of reaction $(i)$ and $(ii)$ are respectively: