Construct $\triangle ABC$ in which $BC = 5\,cm$,$\angle B = 60^{\circ}$ and $AB + AC = 9\,cm$. Write the steps of construction.

(N/A) Steps of construction:
$1$. Draw a line segment $BC = 5\,cm$.
$2$. At point $B$,construct an angle $\angle XBC = 60^{\circ}$.
$3$. Cut a line segment $BD = 9\,cm$ from the ray $BX$.
$4$. Join $CD$.
$5$. Construct the perpendicular bisector of $CD$,which intersects $BD$ at point $A$.
$6$. Join $AC$. Thus,$\triangle ABC$ is the required triangle.