The correct increasing order for the waveleng | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of absorbed light $(\Delta_o)$ is inversely proportional to the wavelength of absorption $(\lambda)$: $\Delta_o \propto \frac{1}{\lambd

Vedclass · Accepted Answer

$[Co(H_2O)_6]^{3+}, [Co(NH_3)_6]^{3+}, [Co(en)_3]^{3+}$

Vedclass · Answer

(B) The energy of absorbed light $(\Delta_o)$ is inversely proportional to the wavelength of absorption $(\lambda)$: $\Delta_o \propto \frac{1}{\lambda}$.
Stronger ligands cause greater crystal field splitting $(\Delta_o)$,which corresponds to higher energy and shorter wavelength of absorption.
The spectrochemical series for the given ligands is: $H_2O < NH_3 < en$.
As the ligand strength increases,the splitting energy $(\Delta_o)$ increases,and therefore the absorbed wavelength $(\lambda)$ decreases.
Thus,the increasing order of wavelength is: $[Co(H_2O)_6]^{3+} < [Co(NH_3)_6]^{3+} < [Co(en)_3]^{3+}$.

List-$I$ (Complex)	List-$II$ (Electronic configuration of metal/ion)
$A. [Co(NH_3)_6]^{3+}$	$I. t_{2g}^5 e_g^0$
$B. [CoF_6]^{3-}$	$II. t_{2g}^6 e_g^0$
$C. [Ni(CO)_4]$	$III. t_{2g}^4 e_g^2$
$D. [Fe(CN)_6]^{3-}$	$IV. t^4 e^6$

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

The correct increasing order for the wavelengths of absorption in the visible region for the complexes of $Co^{3+}$ is:

Similar Questions

What is the correct electronic configuration of the central atom in $K_{4}[Fe(CN)_{6}]$ based on crystal field theory?

Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.
Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

What is the electronic arrangement of a metal atom/ion in an octahedral complex with $d^4$ configuration,if $\Delta_{0} < P$ (pairing energy)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module