Assertion : Potassium ferrocyanide is diamagn | vedclass

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes

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If the Assertion is correct but Reason is incorrect.

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(C) In potassium ferrocyanide,$K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state ($Fe^{2+}$: $3d^6$). Since $CN^-$ is a strong field ligand,it causes pairing of electrons,resulting in $t_{2g}^6 e_g^0$ configuration with $n=0$ unpaired electrons,making it diamagnetic.In potassium ferricyanide,$K_3[Fe(CN)_6]$,$Fe$ is in the $+3$ oxidation state ($Fe^{3+}$: $3d^5$). $CN^-$ causes pairing,resulting in $t_{2g}^5 e_g^0$ configuration with $n=1$ unpaired electron,making it paramagnetic.The Assertion is correct.The Reason states that crystal field splitting in ferrocyanide is greater than in ferricyanide. This is incorrect because crystal field splitting energy $(\Delta_o)$ increases with the oxidation state of the metal ion. Since $Fe^{3+}$ has a higher oxidation state than $Fe^{2+}$,the crystal field splitting in the ferricyanide ion is greater than in the ferrocyanide ion. Thus,the Reason is incorrect.

List-$I$ (Complex)	List-$II$ ($CFSE$ in $\Delta_0$)
$A$. $[Cu(NH_3)_6]^{2+}$	$I$. $-0.6$
$B$. $[Ti(H_2O)_6]^{3+}$	$II$. $-2.0$
$C$. $[Fe(CN)_6]^{3-}$	$III$. $-1.2$
$D$. $[NiF_6]^{4-}$	$IV$. $-0.4$

Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.
Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.

Similar Questions

The correct order of the wavelength of light absorbed by the following complexes is,
$A. [Co(NH_3)_6]^{3+}$
$B. [Co(CN)_6]^{3-}$
$C. [Cu(H_2O)_4]^{2+}$
$D. [Ti(H_2O)_6]^{3+}$
Choose the correct answer from the options given below:

The homoleptic and octahedral complex of $Co^{2+}$ and $H_2O$ has $.......$ unpaired electron$(s)$ in the $t_{2g}$ set of orbitals.

The complex with the highest magnitude of crystal field splitting energy $\left(\Delta_0\right)$ is

The correct increasing order for the wavelengths of absorption in the visible region for the complexes of $Co^{3+}$ is:

Match List-$I$ with List-$II$:

List-$I$ (Complex) List-$II$ ($CFSE$ in $\Delta_0$)

$A$. $[Cu(NH_3)_6]^{2+}$ $I$. $-0.6$

$B$. $[Ti(H_2O)_6]^{3+}$ $II$. $-2.0$

$C$. $[Fe(CN)_6]^{3-}$ $III$. $-1.2$

$D$. $[NiF_6]^{4-}$ $IV$. $-0.4$

Choose the correct answer from the options given below:

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Assertion : Potassium ferrocyanide is diamagnetic,whereas potassium ferricyanide is paramagnetic.Reason : Crystal field splitting in ferrocyanide ion is greater than that of ferricyanide ion.