What is the correct order of K_a values for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The acidic strength is directly proportional to the $K_a$ value and inversely proportional to the $pK_a$ value.Electron-withdrawing groups ($-M$ a

Vedclass · Accepted Answer

$IV > III > II > I$

Vedclass · Answer

(C) The acidic strength is directly proportional to the $K_a$ value and inversely proportional to the $pK_a$ value.Electron-withdrawing groups ($-M$ and $-I$ effects) increase the acidic strength of phenols by stabilizing the phenoxide ion.Compound $(I)$ is phenol.Compound $(II)$ is $o$-nitrophenol ($-I$ and $-M$ effect of one $NO_2$ group).Compound $(III)$ is $p$-nitrophenol ($-I$ and $-M$ effect of one $NO_2$ group).Compound $(IV)$ is $2,4,6$-trinitrophenol (picric acid),which has three $NO_2$ groups exerting strong $-I$ and $-M$ effects.Comparing $(II)$ and $(III)$,$p$-nitrophenol $(III)$ is more acidic than $o$-nitrophenol $(II)$ due to intramolecular hydrogen bonding in $(II)$ which stabilizes the undissociated form.Thus,the order of acidic strength (and $K_a$) is: $(IV) > (III) > (II) > (I)$.

What is the correct order of $K_a$ values for the given compounds?

Similar Questions

Which of the following is most acidic?

Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } CS_2}$ $X$ (Major product)
Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } H_2O}$ $Y$ (Major product)
What are $X$ and $Y$ in the above reaction respectively?

Phenol at $25 \, ^\circ C$ is

What is the product of the sulfonation of phenol?

Which of the following is a characteristic test for the phenolic group?

Vedclass Test Series

Exam Paper Generator

Online Exam Module