Correct order of stability is

  • A
    $CH_3 - \mathop {\ddot C}\limits^\Theta H_2 < CH_2 = \mathop {\ddot C}\limits^\Theta H < CH \equiv \mathop {\ddot C}\limits^\Theta$
  • B
    $CH_3 - \dot CH_2 < CH_2 = \dot CH < CH \equiv \dot C$
  • C
    $CH_3COO^- > C_6H_5O^-$
  • D
    $CH_3 - \mathop C\limits^\oplus H - CH_3 < CH_3 - O - \mathop C\limits^\oplus H_2$

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Similar Questions

The hybridization of the positively charged carbon and the negatively charged carbon in the following structures are respectively:

The correct stability order for the following species is:

The correct stability order for the following species is:
$(I)$ $o-CN-C_6H_4-CH_2^-$
$(II)$ $m-CN-C_6H_4-CH_2^-$
$(III)$ $p-CN-C_6H_4-CH_2^-$
$(IV)$ $C_6H_5-CH_2^-$
(Note: The image shows the structures of these carbanions.)

$A$ certain reaction occurs in two steps as:
$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$
$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$
In the reaction,

Arrange the following carbocations in increasing order of stability:
$1. \, (CH_3)_2 - \overset{+}{C} - CH_2 - CH_3$
$2. \, (CH_3)_3 - \overset{+}{C}$
$3. \, (CH_3)_2 - \overset{+}{C} H$
$4. \, CH_3 - \overset{+}{C} H_2$
$5. \, \overset{+}{C} H_3$

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