The correct order of stability of the given c | vedclass

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(D) The stability of carbanions is determined by factors like aromaticity,resonance,and hybridization.$1$. Compound $(d)$ is the cyclopentadienyl anio

Vedclass · Accepted Answer

$d > c > b > a$

Vedclass · Answer

(D) The stability of carbanions is determined by factors like aromaticity,resonance,and hybridization.$1$. Compound $(d)$ is the cyclopentadienyl anion,which is aromatic ($6\pi$ electrons) and therefore highly stable.$2$. Compound $(a)$ is the cyclopropenyl anion,which is anti-aromatic ($4\pi$ electrons) and therefore the least stable.$3$. Between $(b)$ and $(c)$,both are non-aromatic and the negative charge is on an $sp^3$ hybridized carbon atom. Stability in such cases is influenced by angle strain. The five-membered ring $(c)$ has less angle strain compared to the four-membered ring $(b)$.$4$. Thus,the correct order of stability is $d > c > b > a$.

The correct order of stability of the given carbanions is:

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