The correct stability order of the given taut | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In general,the keto form $(II)$ is more stable than the enol forms ($I$ and $III$) due to the higher bond energy of the $C=O$ bond compared to the

Vedclass · Accepted Answer

$II > I > III$

Vedclass · Answer

(C) In general,the keto form $(II)$ is more stable than the enol forms ($I$ and $III$) due to the higher bond energy of the $C=O$ bond compared to the $C=C$ bond.Between the two enol forms ($I$ and $III$),structure $(I)$ is more stable than structure $(III)$.Structure $(III)$ contains a double bond at the bridgehead position of a bicyclic system involving a three-membered ring,which violates Bredt's rule. This introduces significant angle strain and makes the structure highly unstable.Therefore,the correct stability order is $II > I > III$.

The correct stability order of the given tautomers is:

Similar Questions

The current through the $1 \Omega$ resistance in the following circuit is (in $A$)

$A$ photoelectric cell is illuminated by a point source of light $1\;m$ away. When the source is shifted to $2\;m$,then:

Bulk of carbon dioxide $(CO_2)$ released from body tissues into the blood is present as

$\cos \left[\cos ^{-1}\left(-\frac{1}{7}\right)+\sin ^{-1}\left(-\frac{1}{7}\right)\right]$ is equal to

The product$(s)$ formed when $H_2O_2$ reacts with disodium hydrogen phosphate is

Vedclass Test Series

Exam Paper Generator

Online Exam Module