Which of the following statements is correct?

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(NONE) $1$. Aniline $(C_6H_5NH_2)$ is less soluble in water than methylamine $(CH_3NH_2)$ because the large hydrophobic phenyl group in aniline hinder

Vedclass · Accepted Answer

Ethylamine is more soluble in water than ethanol.

Vedclass · Answer

(NONE) $1$. Aniline $(C_6H_5NH_2)$ is less soluble in water than methylamine $(CH_3NH_2)$ because the large hydrophobic phenyl group in aniline hinders hydrogen bonding with water. Thus,statement $A$ is incorrect.$2$. Ethanol $(C_2H_5OH)$ forms stronger hydrogen bonds with water than ethylamine $(C_2H_5NH_2)$ because oxygen is more electronegative than nitrogen. Thus,statement $B$ is incorrect.$3$. In chlorobenzene,the $C-Cl$ bond is attached to an $sp^2$ hybridized carbon,which is more electronegative,and the lone pairs on $Cl$ are in resonance with the benzene ring,reducing the dipole moment. In cyclohexyl chloride,the $C-Cl$ bond is attached to an $sp^3$ hybridized carbon,which is less electronegative,resulting in a higher dipole moment. Thus,statement $C$ is incorrect.$4$. Since all statements $A$,$B$,and $C$ are incorrect,none of the options provided are correct. However,based on standard chemistry curriculum,if this is a multiple-choice question where one must be selected,there might be an error in the question framing. Given the options,none are factually correct.

Similar Questions

What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

Convert:
$(i)$ $3-$Methylaniline into $3-$nitrotoluene.
$(ii)$ Aniline into $1,3,5-$tribromobenzene.

Heating the acyl azide in dry toluene under reflux for $3$ hours gives a $90\%$ yield for a heterocyclic product. Identify the product $(A)$.

The product of this Hoffmann bromamide reaction is:

The product $(B)$ is:

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