Critical temperature for carbon dioxide and methane are $31.1^{\circ} C$ and $-81.9^{\circ} C$ respectively. Which of these has stronger intermolecular forces and why?

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(A) The critical temperature of a gas is a measure of the strength of intermolecular forces of attraction.
Higher critical temperature indicates that the gas can be liquefied more easily,which implies stronger intermolecular forces of attraction.
Since the critical temperature of $CO_2$ $(31.1^{\circ} C)$ is higher than that of $CH_4$ $(-81.9^{\circ} C)$,$CO_2$ has stronger intermolecular forces of attraction.

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Critical constants for a real gas are given as:
$T_C = 180 \ K$; $V_C = 0.123 \ L \ mol^{-1}$
$P_C = 45 \ atm$; $R = 0.082 \ L \ atm \ mol^{-1} \ K^{-1}$
Which of the following statements is correct for this real gas?

Under what conditions can an ideal gas,which follows the kinetic gas equation,be liquefied?

Assertion : At critical temperature,liquid passes into gaseous state imperceptibly and continuously.
Reason : The density of liquid and gaseous phase is equal at critical temperature.

Which are the most favorable conditions for the liquefaction of a gas?

Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases:
$Gases$$Critical \ temperature \ in \ Kelvin$
$P$$33.2$
$Q$$5.3$
$R$$154.3$
$S$$126$

From the above data,what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first.

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