Current I is flowing in a conductor shaped as | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The conductor consists of three parts: two semi-infinite straight wires ($A$ and $C$) and a three-quarter circular arc $(B)$.$1$. For the straight

Vedclass · Accepted Answer

$\frac{\mu_0 I}{4\pi r} \left( \frac{3\pi}{2} + 1 \right)$

Vedclass · Answer

(A) The conductor consists of three parts: two semi-infinite straight wires ($A$ and $C$) and a three-quarter circular arc $(B)$.$1$. For the straight wire $A$,the point $O$ lies on its axis,so the magnetic field $B_A = 0$.$2$. For the straight wire $C$,the distance from $O$ is $r$. The magnetic field due to a semi-infinite wire at a perpendicular distance $r$ is $B_C = \frac{\mu_0 I}{4\pi r}$. Using the right-hand rule,the direction is into the page $(\otimes)$.$3$. For the three-quarter circular arc $B$,the angle subtended is $	heta = \frac{3\pi}{2}$. The magnetic field is $B_B = \frac{\mu_0 I 	heta}{4\pi r} = \frac{\mu_0 I (3\pi/2)}{4\pi r}$. The direction is also into the page $(\otimes)$.$4$. The net magnetic field at $O$ is $B_{net} = B_A + B_B + B_C = 0 + \frac{\mu_0 I}{4\pi r} \left( \frac{3\pi}{2} ight) + \frac{\mu_0 I}{4\pi r} = \frac{\mu_0 I}{4\pi r} \left( \frac{3\pi}{2} + 1 ight)$.

Current $I$ is flowing in a conductor shaped as shown in the figure. The radius of the curved part is $r$ and the length of the straight portions is very large. The value of the magnetic field at the centre $O$ will be

Similar Questions

If $\frac{\tan 3A}{\tan A} = a$,then $\frac{\sin 3A}{\sin A}$ is equal to

If the circles $x^2+y^2-2 \lambda x-2 y-7=0$ and $3(x^2+y^2)-8 x+29 y=0$ are orthogonal,then $\lambda$ is equal to

If the number of diagonals of a regular polygon is $35$,then the number of sides of the polygon is

Which of the following is an essential amino acid?

$A$ particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement $x$ is proportional to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module