The curve $16x^2 + 8xy + y^2 - 74x - 78y + 212 = 0$ represents:

The lines $y = -\frac{3}{2} x$ and $y = -\frac{2}{5} x$ intersect the curve $3x^2 + 4xy + 5y^2 - 4 = 0$ at the points $P$ and $Q$ respectively. The tangents drawn to the curve at $P$ and $Q$:

Find the center of the conic $14x^2 - 4xy + 11y^2 - 44x - 58y + 71 = 0$.

The equation $16 x^2+y^2+8 x y-74 x-78 y+212=0$ represents

The centre of the conic represented by the equation $2x^2 - 72xy + 23y^2 - 4x - 28y - 48 = 0$ is

The equation $8 x^2+12 y^2-4 x+4 y-1=0$ represents