The decreasing order of stability of O_2, O_{ | vedclass

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(D) Stability is directly proportional to the bond order of the species.$1$. Calculate the total number of electrons and bond order $(B.O.)$ for each

Vedclass · Accepted Answer

$O_2^{+} > O_2 > O_{2}^{-} > O_2^{2-}$

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(D) Stability is directly proportional to the bond order of the species.$1$. Calculate the total number of electrons and bond order $(B.O.)$ for each species:- $O_2^{+}$ $(15 \ e^{-})$: $B.O. = 2.5$- $O_2$ $(16 \ e^{-})$: $B.O. = 2.0$- $O_2^{-}$ $(17 \ e^{-})$: $B.O. = 1.5$- $O_2^{2-}$ $(18 \ e^{-})$: $B.O. = 1.0$$2$. Since stability $\propto B.O.$,the decreasing order of stability is:$O_2^{+} > O_2 > O_2^{-} > O_2^{2-}$

The decreasing order of stability of $O_2, O_{2}^{-}, O_{2}^{+}$ and $O_2^{2-}$ is:

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