The decreasing order of reactivity towards S_ | vedclass

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Question

(C) The rate of $S_N 1$ reaction depends upon the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$.E

Vedclass · Accepted Answer

$b > d > c > a$

Vedclass · Answer

(C) The rate of $S_N 1$ reaction depends upon the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$.Electron-donating groups (like $-OCH_3$) increase the stability of the carbocation,while electron-withdrawing groups (like $-NO_2$ and $-Cl$) decrease its stability.The stability order of the carbocations is:$p-methoxybenzyl$ carbocation $(b)$ $>$ $benzyl$ carbocation $(d)$ $>$ $p-chlorobenzyl$ carbocation $(c)$ $>$ $p-nitrobenzyl$ carbocation $(a)$.Therefore,the decreasing order of reactivity towards $S_N 1$ reaction is:$(b) > (d) > (c) > (a)$.

The decreasing order of reactivity towards $S_N 1$ reaction for the following compounds is:

Similar Questions

Predict the order of reactivity of the following compounds in $S_N1$ reaction.
$(I)$ $C_6H_5-CH_2Br$
$(II)$ $C_6H_5-CH(C_6H_5)Br$
$(III)$ $C_6H_5-CH(CH_3)Br$
$(IV)$ $C_6H_5-C(CH_3)(C_6H_5)Br$

An alkyl bromide $(A)$ forms a Grignard reagent which on treatment with water yields $n$-hexane. When $(A)$ is treated with sodium in dry ether,$4,5$-diethyloctane is formed. The structure of $(A)$ is:

Which of the following is the correct order of boiling points for alkyl halides?

The major product of the following reaction is:

Which of the compounds will react faster in an $S_N1$ reaction?
$CH_3-CH_2-Cl$ and $C_6H_5-CH_2-Cl$

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