Define an isobaric process. Derive an expression for the work done in such a process.

(N/A) An isobaric process is a thermodynamic process in which the pressure of the system remains constant.
Consider a gas undergoing an expansion from an initial state $(V_1, P)$ to a final state $(V_2, P)$ at a constant pressure $P$,as shown in the $P-V$ diagram.
The work done $W$ by the gas is given by the integral of pressure with respect to volume:
$W = \int_{V_1}^{V_2} P \, dV$
Since the pressure $P$ is constant,it can be taken out of the integral:
$W = P \int_{V_1}^{V_2} dV$
$W = P [V_2 - V_1]$
$W = P \Delta V$
Using the ideal gas equation $PV = \mu RT$,we can express the work done in terms of temperature change:
$PV_1 = \mu RT_1$
$PV_2 = \mu RT_2$
Substituting these into the work equation:
$W = \mu RT_2 - \mu RT_1$
$W = \mu R(T_2 - T_1)$
$W = \mu R \Delta T$