Dehydration of ethanol gives

What is the major product of the following reaction?

Which of the following reactions proceeds via a secondary free radical?

$but-2-yne$ is reacted separately with one mole of $H_2$ as shown below:
$\underline{ B } \xleftarrow[\text{liq } NH_3]{Na} CH_3-C \equiv C-CH_3 \xrightarrow[\Delta]{Pd/C} \underline{ A }$
Identify the incorrect statements from the options given below:
$A.$ $A$ is more soluble than $B$.
$B.$ The boiling point and melting point of $A$ are higher and lower than $B$ respectively.
$C.$ $A$ is more polar than $B$ because dipole moment of $A$ is zero.
$D.$ $Br_2$ adds easily to $B$ than $A$.

The compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives:

Which of the following compounds is formed as the major product in the following reaction?
$2-\text{methylbut-}2-\text{ene} \xrightarrow[\text{Peroxide}]{HBr} \text{Product}$