The compound CH_3-C(CH_3)=CH-CH_3 on reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of an alkene with $NaIO_4$ in the presence of $KMnO_4$ (Lemieux-von Rudloff reagent) results in the oxidative cleavage of the $C=C$ d

Vedclass · Accepted Answer

$CH_3COCH_3 + CH_3COOH$

Vedclass · Answer

(D) The reaction of an alkene with $NaIO_4$ in the presence of $KMnO_4$ (Lemieux-von Rudloff reagent) results in the oxidative cleavage of the $C=C$ double bond.In the compound $CH_3-C(CH_3)=CH-CH_3$,the double bond is cleaved.The substituted carbon $CH_3-C(CH_3)=$ is oxidized to a ketone,$CH_3COCH_3$ (acetone).The $=CH-CH_3$ part is oxidized to an aldehyde,which is further oxidized to a carboxylic acid,$CH_3COOH$ (acetic acid),under these conditions.Therefore,the final products are $CH_3COCH_3 + CH_3COOH$.

The compound $CH_3-C(CH_3)=CH-CH_3$ on reaction with $NaIO_4$ in the presence of $KMnO_4$ gives:

Similar Questions

What is the product of the reaction of $CH_3CH=CH-C_6H_4-OH$ with $HBr$?

For the given reaction sequence,identify the products $(C)$ and $(D)$ formed after ozonolysis of the major product $(B)$:
$(CH_3)_2CH-CHCl-CH_3$ $\xrightarrow{C_2H_5ONa / C_2H_5OH} B$ $\xrightarrow{O_3 / H_2O_2} C + D$

Addition of $OsO_4$ to cyclopentene would give a product which is

Out of the following,the alkene that exhibits optical isomerism is

What is the major product of the reaction $CH_2 = CH-(CH_2)_8COOH + HBr \xrightarrow{\text{Peroxide}} \dots$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module