Determine the hybridisation,magnetic nature,a | vedclass

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(D) $1$. The central metal ion is $Co^{3+}$. The electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$. Thus,$Co^{3+}$ is $[Ar] 3d^6$.$2$. The

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$d^2sp^3$; Diamagnetic; $0 \ B.M.$

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(D) $1$. The central metal ion is $Co^{3+}$. The electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$. Thus,$Co^{3+}$ is $[Ar] 3d^6$.$2$. The ligand $C_2O_4^{2-}$ (oxalate) is a strong field ligand $(SFL)$ for $Co^{3+}$,causing pairing of electrons in the $3d$ orbitals.$3$. The $6$ electrons in $3d$ orbitals pair up to occupy $3$ orbitals,leaving $2$ $d$-orbitals empty for hybridisation.$4$. The hybridisation is $d^2sp^3$,which corresponds to an inner orbital octahedral complex.$5$. Since all electrons are paired,the complex is diamagnetic.$6$. The spin-only magnetic moment $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons. Here $n=0$,so $\mu = 0 \ B.M.$

Determine the hybridisation,magnetic nature,and spin-only magnetic moment for $[Co(C_2O_4)_3]^{3-}$

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