The diazonium salt decomposes as C_6H_5N_2^+C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate law for the reaction is given by $Rate = k[C_6H_5N_2^+Cl^-]^n$,where $n$ is the order of the reaction.Given that when the initial concent

Vedclass · Accepted Answer

$A$. $A$ first order reaction

Vedclass · Answer

(A) The rate law for the reaction is given by $Rate = k[C_6H_5N_2^+Cl^-]^n$,where $n$ is the order of the reaction.Given that when the initial concentration is doubled,the rate of evolution of $N_2$ (which is the rate of reaction) becomes two times faster.Let the initial rate be $R_1 = k[C]^n$ and the new rate be $R_2 = k[2C]^n$.According to the problem,$R_2 = 2R_1$.Therefore,$k[2C]^n = 2 	imes k[C]^n$.$2^n = 2^1$.Thus,$n = 1$.Hence,it is a first order reaction.

The diazonium salt decomposes as $C_6H_5N_2^+Cl^- \to C_6H_5Cl + N_2$. At $0 \ ^\circ C$,the evolution of $N_2$ becomes two times faster when the initial concentration of the salt is doubled. Therefore,it is:

Similar Questions

The rate of reaction,$A + B \rightarrow \text{product}$,is $7.2 \times 10^{-2} \ mol \ dm^{-3} \ s^{-1}$ at $[A] = 0.4 \ mol \ dm^{-3}$ and $[B] = 0.1 \ mol \ dm^{-3}$. The reaction is first order in $A$ and second order in $B$. Calculate the rate constant.

The unit of the rate constant depends on which of the following?

Which one of the following is wrongly matched?

For the reaction $A + B \rightarrow \text{Product}$,the rate law is given by $\text{Rate} = K[A]^1[B]^2$. Which of the following statements is incorrect?

What is a pseudo first order reaction? Give an example of a pseudo first order reaction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module