Domain of the function log |x^2 - 9| is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The function $f(x) = \log |x^2 - 9|$ is defined only when the argument of the logarithm is strictly positive.That is,$|x^2 - 9| > 0$.Since the abs

Vedclass · Accepted Answer

$R - \{-3, 3\}$

Vedclass · Answer

(C) The function $f(x) = \log |x^2 - 9|$ is defined only when the argument of the logarithm is strictly positive.That is,$|x^2 - 9| > 0$.Since the absolute value $|x^2 - 9|$ is always non-negative,the condition $|x^2 - 9| > 0$ is satisfied for all real numbers $x$ except where $|x^2 - 9| = 0$.Setting $x^2 - 9 = 0$,we get $x^2 = 9$,which implies $x = 3$ or $x = -3$.Therefore,the function is undefined at $x = 3$ and $x = -3$.Thus,the domain of the function is all real numbers except $\{-3, 3\}$,which is written as $R - \{-3, 3\}$.

Domain of the function $\log |x^2 - 9|$ is

Similar Questions

Write down the power set of $C = \{1, \{2\}\}$.

If $A = \{2, 3, 5\}$ and $B = \{2, 5, 6\}$,then $(A - B) \times (A \cap B)$ is:

If $A = \{2, 3, 4, 8, 10\}, B = \{3, 4, 5, 10, 12\}, C = \{4, 5, 6, 12, 14\}$,then $(A \cap B) \cup (A \cap C)$ is equal to

Set $A$ has $m$ elements and Set $B$ has $n$ elements. If the total number of subsets of $A$ is $112$ more than the total number of subsets of $B$,then the value of $m \times n$ is

$A - (A - B)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module