Draw the graph of the following linear equation in two variables:
$4x - 3y = 12$

(N/A) $4x - 3y = 12$
$\therefore 4x - 12 = 3y$
$\therefore y = \frac{4x - 12}{3}$
For $x = 0$,we get:
$y = \frac{4(0) - 12}{3} = \frac{-12}{3} = -4$; i.e.,$y = -4$
For $x = 3$,we get:
$y = \frac{4(3) - 12}{3} = \frac{0}{3} = 0$; i.e.,$y = 0$
For $x = 6$,we get:
$y = \frac{4(6) - 12}{3} = \frac{12}{3} = 4$; i.e.,$y = 4$
We can represent these solutions in the tabular form as below:

$x$	$0$	$3$	$6$
$y$	$-4$	$0$	$4$

Plot the points $(0, -4)$,$(3, 0)$,and $(6, 4)$ on a Cartesian plane and join them to obtain the graph of the line $4x - 3y = 12$.