Draw the graph of the linear equation $2x + 3y = 12$. At what points does the graph of the equation cut the $x$-axis and the $y$-axis?

(N/A) The given equation is $2x + 3y = 12$. To draw the graph of this equation,we need at least two points lying on the graph.
From the equation,we have $y = \frac{12 - 2x}{3}$.
For $x = 0$,$y = \frac{12 - 0}{3} = 4$. Therefore,$(0, 4)$ lies on the graph.
For $y = 0$,$2x = 12$,so $x = 6$. Therefore,$(6, 0)$ lies on the graph.
Now,plot the points $A(0, 4)$ and $B(6, 0)$ and join them to get the line $AB$.
Line $AB$ is the required graph. The graph (line $AB$) cuts the $x$-axis at the point $(6, 0)$ and the $y$-axis at the point $(0, 4)$.