During the electrolysis of concentrated $H_2SO_4$,perdisulphuric acid $(H_2S_2O_8)$ and $O_2$ are formed in equimolar amounts. The amount of $H_2$ that will be formed simultaneously is $(2H_2SO_4 \rightarrow H_2S_2O_8 + 2H^+ + 2e^-)$

  • A
    thrice that of $O_2$ in moles
  • B
    twice that of $O_2$ in moles
  • C
    equal to that of $O_2$ in moles
  • D
    half of that of $O_2$ in moles

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