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(C) During anaerobic respiration,the breakdown of one glucose molecule produces a net gain of $2$ $ATP$ molecules.This occurs because,during glycolysi

Vedclass · Accepted Answer

$40$

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(C) During anaerobic respiration,the breakdown of one glucose molecule produces a net gain of $2$ $ATP$ molecules.This occurs because,during glycolysis,a total of $4$ $ATP$ molecules are produced,but $2$ $ATP$ molecules are consumed in the preparatory phase,resulting in a net gain of $2$ $ATP$ molecules.Since anaerobic respiration does not involve the electron transport chain or oxidative phosphorylation,no additional $ATP$ molecules are generated beyond those produced during glycolysis.Therefore,the number of $ATP$ molecules generated by the breakdown of $20$ glucose molecules is calculated as: $20 	ext{ glucose molecules} 	imes 2 	ext{ } ATP 	ext{ molecules/glucose} = 40 	ext{ } ATP 	ext{ molecules}$.Thus,the correct answer is $40$ $ATP$ molecules.

During anaerobic respiration,the number of $ATP$ molecules generated by the breakdown of $20$ glucose molecules is . . . . . . .

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