During the electrolytic reduction of alumina,the reaction at cathode is
- A$2 H_2 O \longrightarrow O_2 + 4 H^{+} + 4 e^{-}$
- B$3 F^{-} \longrightarrow 3 F + 3 e^{-}$
- C$Al^{3+} + 3 e^{-} \longrightarrow Al$
- D$2 H^{+} + 2 e^{-} \longrightarrow H_2$
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