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(D) The original alphabet is: $A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z$.According to the rule,alternate letters s

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$ocToBeR$

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(D) The original alphabet is: $A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z$.According to the rule,alternate letters starting from $A$ are written in small letters $(a, c, e, g, i, k, m, o, q, s, u, w, y)$ and the rest are in capital letters $(B, D, F, H, J, L, N, P, R, T, V, X, Z)$.The modified series is: $a, B, c, D, e, F, g, H, i, J, k, L, m, N, o, P, q, R, s, T, u, V, w, X, y, Z$.The third month after July is October.Mapping the letters of '$OCTOBER$' to the new series:$O \rightarrow o$$C \rightarrow c$$T \rightarrow T$$O \rightarrow o$$B \rightarrow B$$E \rightarrow e$$R \rightarrow R$Thus,'$OCTOBER$' is written as '$ocToBeR$'.

Similar Questions

Each of the following questions is based on the following alphabet series.
$A, B, C, D, E, F, G, H, I, J, K, L, M$
$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$
If the above alphabets were written in the reverse order,which will be the fifth letter to the left of the ninth letter from the right?

Study the letter series given below and answer the questions that follow:
$H, D, Y, S, M, W, N, B, Q, P, O, C, R, T, B, L, Z, V, E, G, U, F$
Which two neighbours in the given arrangement are farthest in the alphabetical order?

If the letters of the word $HANDOVER$ are arranged alphabetically from left to right,how many letters will remain at the same position?

Arrange the given words in alphabetical order and choose the one that comes in the second place:

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