The energy $E$ of a hydrogen atom with principal quantum number $n$ is given by $E = \frac{-13.6}{n^2} \; eV$. The energy of a photon emitted when the electron jumps from the $n = 3$ state to the $n = 2$ state of hydrogen is approximately......$eV$.

  • A
    $1.5$
  • B
    $0.85$
  • C
    $3.4$
  • D
    $1.9$

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