Energy of a photon is 1 MeV, then its moment | vedclass

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Question

(A) The momentum $P$ of a photon is given by the relation $P = \frac{E}{c},$ where $E$ is the energy and $c$ is the speed of light.Given $E = 1 \ MeV

Vedclass · Accepted Answer

$0.53 	imes 10^{-21} \ kg \ ms^{-1}$

Vedclass · Answer

(A) The momentum $P$ of a photon is given by the relation $P = \frac{E}{c},$ where $E$ is the energy and $c$ is the speed of light.Given $E = 1 \ MeV = 1 	imes 10^6 \ eV = 1 	imes 10^6 	imes 1.602 	imes 10^{-19} \ J = 1.602 	imes 10^{-13} \ J.$Speed of light $c = 3 	imes 10^8 \ ms^{-1}.$$P = \frac{1.602 	imes 10^{-13} \ J}{3 	imes 10^8 \ ms^{-1}} = 0.534 	imes 10^{-21} \ kg \ ms^{-1}.$

Energy of a photon is $1 \ MeV,$ then its momentum will be $:-$

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