The greater the energy of a photon,the

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(C) The energy of a photon is given by the equations $E = \frac{hc}{\lambda}$ and $E = hv$,where $h$ is Planck's constant,$c$ is the speed of light,$\

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shorter the wavelength and the higher the frequency

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(C) The energy of a photon is given by the equations $E = \frac{hc}{\lambda}$ and $E = hv$,where $h$ is Planck's constant,$c$ is the speed of light,$\lambda$ is the wavelength,and $v$ is the frequency.From $E = hv$,it is clear that energy is directly proportional to frequency $(E \propto v)$,so higher energy means higher frequency.From $E = \frac{hc}{\lambda}$,it is clear that energy is inversely proportional to wavelength $(E \propto \frac{1}{\lambda})$,so higher energy means shorter wavelength.

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