Energy required to establish a current of $4 \ A$ in a coil of self-inductance $L = 200 \ mH$ is . . . . . . . (in $J$)

$A$ coil of resistance $10 \, \Omega$ and an inductance $5 \, H$ is connected to a $100 \, V$ battery. The energy stored in the coil is:

If a current flowing in a coil is reduced to half of its initial value,the relation between the new energy $(E_2)$ and the original energy $(E_1)$ stored in the coil will be

The energy stored in a $50 \, mH$ inductor carrying a current of $4 \, A$ will be $J$.

If the current in a coil is halved,then the energy stored becomes how many times the previous value?

When a current $I$ flows through a coil,it stores the energy $E_1$ in it. Now the current is reduced to $I/2$,the energy stored in the coil becomes $E_2$. The change in the energy is