Equal masses of three non-reacting different | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The average kinetic energy per mole of an ideal gas is given by the formula $KE_{avg} = \frac{3}{2} RT$.$2$. Since the temperature $T$ is con

Vedclass · Accepted Answer

Average kinetic energy per mole of gas $X$ is highest.

Vedclass · Answer

(B) $1$. The average kinetic energy per mole of an ideal gas is given by the formula $KE_{avg} = \frac{3}{2} RT$.$2$. Since the temperature $T$ is constant at $400 \ K$ for all gases in the mixture,the average kinetic energy per mole for all gases $(X, Y, Z)$ must be identical $(KE_{avg} = \frac{3}{2} R(400))$.$3$. Therefore,the statement that the average kinetic energy per mole of gas $X$ is the highest is physically impossible,as it must be equal to the others.$4$. Option $A$ is possible depending on the molar masses.$5$. Option $C$ is a property of ideal gases (they cannot be liquefied).$6$. Option $D$ is correct based on the ideal gas law $P_X = \frac{n_X RT}{V}$.

Column-$I$	Column-$II$
$A$. Hydrogen gas $(P=200 \ atm, T=273 \ K)$	$p$. Compressibility factor $Z \neq 1$
$B$. Hydrogen gas $(P \approx 0, T=273 \ K)$	$q$. Attractive forces are dominant
$C$. $CO_2$ $(P=1 \ atm, T=273 \ K)$	$r$. $PV=nRT$
$D$. Real gas with very large molar volume	$s$. $P(V_m-b)=RT$

Equal masses of three non-reacting different ideal gases $X, Y$ and $Z$ are mixed in a sealed rigid container. If the temperature of the system remains constant at $400 \ K$,which of the following statements about gas $X$ can never be correct?

Similar Questions

In a container,$0.5 \ mol$ each of $H_2, SO_2$,and $CH_4$ are taken. The order of their partial pressures after $3$ hours will be:

Which of the following graphs represents the behavior of one mole of an ideal gas at $1 \ atm$ pressure for volume $V$ versus temperature $T$?

The total pressure of a gas and a few drops of water in a container is $830 \, mm$. If the temperature of the container is decreased by $1 \%$,the new pressure is $............ \, mm$. The water vapor pressures at the two temperatures are $30 \, mm$ and $25 \, mm$ respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module