Ethanol and phenol cannot be distinguished by

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. $I_2/NaOH$ (Iodoform test): Ethanol gives a positive iodoform test (yellow precipitate),whereas phenol does not. Thus,they can be distinguish

Vedclass · Accepted Answer

$NaHCO_3$

Vedclass · Answer

(D) $1$. $I_2/NaOH$ (Iodoform test): Ethanol gives a positive iodoform test (yellow precipitate),whereas phenol does not. Thus,they can be distinguished.$2$. Neutral $FeCl_3$: Phenol gives a violet color with neutral $FeCl_3$ solution,while ethanol does not. Thus,they can be distinguished.$3$. $Br_2/H_2O$: Phenol gives a white precipitate of $2,4,6-tribromophenol$ with bromine water,while ethanol does not react. Thus,they can be distinguished.$4$. $NaHCO_3$: Neither ethanol nor phenol is acidic enough to react with $NaHCO_3$ to evolve $CO_2$ gas. Therefore,they cannot be distinguished by this reagent.

Column $(I)$	Column $(II)$	Column $(III)$
$(A)$ Methyl isopropyl ether	$(1)$ ${C_6}{H_5}O{(CH_2)_6}CH_3$	$(i)$ $2$-Methoxypropane
$(B)$ Phenyl isopentyl ether	$(2)$ $CH_3-O-CH(CH_3)_2$	$(ii)$ Methoxyethane
$(C)$ Heptyl phenyl ether	$(3)$ ${C_6}{H_5}-O-CH_2CH_2CH(CH_3)_2$	$(iii)$ $1$-Phenoxyheptane
$(D)$ Ethyl methyl ether	$(4)$ $CH_3CH_2-O-CH_3$	$(iv)$ $1$-Methoxy$-3-$methylbutane (or $3$-Methylbutoxybenzene)

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. Cumene $+ O_2$	$i$. Phenol
$B$. Benzene sulphonic acid $\xrightarrow{NaOH, H^+}$	$ii$. $2$-Methylbutan-$1$-ol
$C$. Chlorobenzene $+ NaOH \xrightarrow{623 \ K, 300 \ atm}$	$iii$. Cumene hydroperoxide
$D$. $2$-Methylbutanal $\xrightarrow{NaBH_4}$	$iv$. Sodium phenoxide

Similar Questions

Major product of the reaction is

Ethanol is prepared industrially by

The reaction of elemental sulphur with a Grignard reagent followed by acidification leads to the formation of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module