Ethylene reacts with bromine to form

Suppose the following reaction sequence: $CH \equiv CH$ $\xrightarrow[\text{excess}]{NaNH_2 / \text{liq. } NH_3} A$ $\xrightarrow{2 CH_3 - I} B$ $\xrightarrow{H_2 / Pd - BaSO_4, \text{ quinoline}} C$ and $C$ $\xrightarrow{H_2 / Pd - BaSO_4, \text{ quinoline}}$ $\xrightarrow{NaNH_2 / \text{liq. } NH_3} D$. How are $C$ and $D$ related?

What are the suitable conditions for the following transformation?

What is the major product of the reaction $CH_2 = CH-(CH_2)_8COOH + HBr \xrightarrow{\text{Peroxide}} \dots$?

Consider compounds $A$, $B$, and $C$ with the following structural formulae:
$A = CH_3 - CH_2 - CH_2 - CH_2 - CH_2 - OH$
$B = CH_2 = CH - CH_2 - CH_2 - CH_3$
$C = HO - CH_2 - CH_2 - CH(OH) - CH_3$
For the conversion of $B$ from $A$, the reagent $(D)$ required is . . . . . . and the structural formula of the product $(E)$ obtained when $C$ undergoes the same reaction using excess reagent $(D)$ is . . . . . . .

The addition of $HBr$ is easiest with