આપેલ લક્ષની કિંમત શોધો: mathop {lim }limits_{ | vedclass

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Question

(A) $x=3$ આગળ,આપેલ પદાવલિ $\frac{0}{0}$ અનિશ્ચિત સ્વરૂપ ધારણ કરે છે.$\mathop {\lim }\limits_{x 	o 3} \frac{x^{4}-81}{2 x^{2}-5 x-3} = \mathop {\lim }

Vedclass · Accepted Answer

$\frac{108}{7}$

Vedclass · Answer

(A) $x=3$ આગળ,આપેલ પદાવલિ $\frac{0}{0}$ અનિશ્ચિત સ્વરૂપ ધારણ કરે છે.$\mathop {\lim }\limits_{x 	o 3} \frac{x^{4}-81}{2 x^{2}-5 x-3} = \mathop {\lim }\limits_{x 	o 3} \frac{(x^2-9)(x^2+9)}{(2x+1)(x-3)}$$= \mathop {\lim }\limits_{x 	o 3} \frac{(x-3)(x+3)(x^2+9)}{(2x+1)(x-3)}$$= \mathop {\lim }\limits_{x 	o 3} \frac{(x+3)(x^2+9)}{2x+1}$$= \frac{(3+3)(3^2+9)}{2(3)+1}$$= \frac{6 	imes 18}{7} = \frac{108}{7}$

આપેલ લક્ષની કિંમત શોધો: $\mathop {\lim }\limits_{x \to 3} \frac{x^{4}-81}{2 x^{2}-5 x-3}$

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