Evaluate the sum: $\sum\limits_{k = 1}^n {\frac{1}{{{{\log }_{{2^k}}}(a)}}}$

  • A
    $\frac{{n(n + 1)}}{2}{\log _a}2$
  • B
    $\frac{{n(n + 1)}}{2}{\log _2}a$
  • C
    $\frac{{{{(n + 1)}^2}{n^2}}}{4}{\log _2}a$
  • D
    None of these

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