(D) To evaluate $(998)^{3}$,we can express $998$ as $(1000 - 2)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$,where $a = 10

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(D) To evaluate $(998)^{3}$,we can express $998$ as $(1000 - 2)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$,where $a = 1000$ and $b = 2$:$(1000 - 2)^{3} = (1000)^{3} - (2)^{3} - 3(1000)(2)(1000 - 2)$$= 1,000,000,000 - 8 - 6000(998)$$= 1,000,000,000 - 8 - 5,988,000$$= 994,011,992$

Class 9 Mathematics Polynomials Mix Examples - Polynomials

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Evaluate using suitable identities: $(998)^{3}$

A
$894041942$
B
$894051922$
C
$9961196$
D
$994011992$

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Mix Examples - Polynomials

Check whether $p(x)$ is a multiple of $g(x)$ or not:
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Evaluate using suitable identities: $(998)^{3}$

Similar Questions

Check whether $p(x)$ is a multiple of $g(x)$ or not:$p(x) = x^{3} - 5x^{2} + 4x - 3, \quad g(x) = x - 2$

Write the coefficient of $x^{2}$ in the following polynomial:$\pi x^{2}-\frac{22}{7} x+3.14$

Factorise $: 4 x^{2}+4 x y-3 y^{2}$

Find the quotient and the remainder when $2x^{2}-7x-15$ is divided by $2x+1$.

Factorise the following quadratic polynomial by splitting the middle term:$x^{2}-4x-77$

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Check whether $p(x)$ is a multiple of $g(x)$ or not:
$p(x) = x^{3} - 5x^{2} + 4x - 3, \quad g(x) = x - 2$

Write the coefficient of $x^{2}$ in the following polynomial:
$\pi x^{2}-\frac{22}{7} x+3.14$

Factorise the following quadratic polynomial by splitting the middle term:
$x^{2}-4x-77$