Examine whether the following equation is qua | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine if the equation $16x^2 - 3 = (2x + 5)(5x - 3)$ is quadratic,we first expand the right side:$(2x + 5)(5x - 3) = 2x(5x) + 2x(-3) + 5(5x

Vedclass · Accepted Answer

Yes,it is a quadratic equation.

Vedclass · Answer

(A) To determine if the equation $16x^2 - 3 = (2x + 5)(5x - 3)$ is quadratic,we first expand the right side:$(2x + 5)(5x - 3) = 2x(5x) + 2x(-3) + 5(5x) + 5(-3)$$= 10x^2 - 6x + 25x - 15$$= 10x^2 + 19x - 15$Now,substitute this back into the original equation:$16x^2 - 3 = 10x^2 + 19x - 15$Rearrange all terms to one side to set the equation to $0$:$16x^2 - 10x^2 - 19x - 3 + 15 = 0$$6x^2 - 19x + 12 = 0$Since this equation is in the form $ax^2 + bx + c = 0$ where $a 
eq 0$,it is a quadratic equation.

Examine whether the following equation is quadratic or not: $16x^2 - 3 = (2x + 5)(5x - 3)$

Similar Questions

If the roots of the quadratic equation $x(x+1)-6=0$ are

Find whether the following equation has real roots. If real roots exist,find them.
$\frac{1}{2x-3} + \frac{1}{x-5} = 1, x \neq \frac{3}{2}, 5$

The formula for finding the value of $D$ (discriminant) for a quadratic equation $ax^2 + bx + c = 0$ is $\ldots \ldots \ldots \ldots.$

Obtain the roots of the following equation using the method of 'completing the square': $16x^{2} - 24x - 1 = 0$.

Solve the following quadratic equation using the method of 'completing the square': $2x^2 - 7x + 3 = 0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module