Expand the expression $(2x - 3)^6$.

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Using the Binomial Theorem,the expansion of $(a + b)^n$ is given by $\sum_{k=0}^{n} {^nC_k} a^{n-k} b^k$.
For the expression $(2x - 3)^6$,we have $a = 2x$,$b = -3$,and $n = 6$.
$(2x - 3)^6 = {^6C_0}(2x)^6(-3)^0 + {^6C_1}(2x)^5(-3)^1 + {^6C_2}(2x)^4(-3)^2 + {^6C_3}(2x)^3(-3)^3 + {^6C_4}(2x)^2(-3)^4 + {^6C_5}(2x)^1(-3)^5 + {^6C_6}(2x)^0(-3)^6$
$= 1(64x^6)(1) + 6(32x^5)(-3) + 15(16x^4)(9) + 20(8x^3)(-27) + 15(4x^2)(81) + 6(2x)(-243) + 1(1)(729)$
$= 64x^6 - 576x^5 + 2160x^4 - 4320x^3 + 4860x^2 - 2916x + 729$.

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